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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: oompaloo on October 27, 2005, 07:42:24 PM

Title: vapor composition of hexane and pentane solution
Post by: oompaloo on October 27, 2005, 07:42:24 PM
Does anyone know how to figure out the vapor composition of an 80% hexane and 20% pentane solution when the vapor is condensed and the liquid below is heated?  Thanks in advance!
Title: Re:vapor composition of hexane and pentane solution
Post by: mike on October 27, 2005, 08:08:18 PM
Psolvent = Xsolvent x Posolvent   [Raoult's Law]

X = mole fraction of solvent
P = vapour pressure of pure solvent

Ptotal = Psolvent1 + Psolvent2 [Dalton's Law]

Ptotal = Xsolvent1 x Posolvent1 + (1 - Xsolvent1) x Posolvent2

These equations might help (?)
Title: Re:vapor composition of hexane and pentane solution
Post by: oompaloo on October 27, 2005, 08:45:09 PM
I have those formulas but I have no idea where to find the numbers to plug into those equations???  The only information I have is a solution containing 80% hexane and 20% pentane.  How do you figure out the numbers to plug into the equations???
Title: Re:vapor composition of hexane and pentane solution
Post by: mike on October 27, 2005, 08:51:20 PM
I would have thought you could work out the partial pressure of hexane and pentane for 80% and 20% (0.8 and 0.2 mole fraction) and then the partial pressures would be proportional to the amount of vapour.
Title: Re:vapor composition of hexane and pentane solution
Post by: mike on October 27, 2005, 09:04:04 PM
For example:

mole fraction of solvent 1 in vapour is:

P1/Ptotal

P1/P1+P2 = Xsolvent1xPosolvent1/Xsolvent1 x Posolvent1 + (1 - Xsolvent1) x Posolvent2

 :) :)