Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: oompaloo on October 27, 2005, 07:42:24 PM
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Does anyone know how to figure out the vapor composition of an 80% hexane and 20% pentane solution when the vapor is condensed and the liquid below is heated? Thanks in advance!
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Psolvent = Xsolvent x Posolvent [Raoult's Law]
X = mole fraction of solvent
P = vapour pressure of pure solvent
Ptotal = Psolvent1 + Psolvent2 [Dalton's Law]
Ptotal = Xsolvent1 x Posolvent1 + (1 - Xsolvent1) x Posolvent2
These equations might help (?)
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I have those formulas but I have no idea where to find the numbers to plug into those equations??? The only information I have is a solution containing 80% hexane and 20% pentane. How do you figure out the numbers to plug into the equations???
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I would have thought you could work out the partial pressure of hexane and pentane for 80% and 20% (0.8 and 0.2 mole fraction) and then the partial pressures would be proportional to the amount of vapour.
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For example:
mole fraction of solvent 1 in vapour is:
P1/Ptotal
P1/P1+P2 = Xsolvent1xPosolvent1/Xsolvent1 x Posolvent1 + (1 - Xsolvent1) x Posolvent2
:) :)