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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: ixi on December 06, 2007, 08:57:04 PM

Title: reactions
Post by: ixi on December 06, 2007, 08:57:04 PM

d/dt= KA[A]0e^(-KAt)-KI
the book says this is a differential equation that when solved yields the following expression for

= (KA/(KI-KA))(e^(-KAT)-e^(-KIT)) [A]O

what do i do to get this? I think i have to take the derivative of the first equation...? i'm not sure where to get started 

Title: Re: reactions
Post by: Padfoot on December 06, 2007, 09:44:23 PM

Quote from: ixi on December 06, 2007, 08:57:04 PM

d/dt= KA[A]0e^(-KAt)-KI
what do i do to get this? I think i have to take the derivative of the first

Solving a differential equation usually means finding the integral.

Integrating exponentials: http://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/expondirectory/Exponentials.html

This post probably belongs in the Math Forum though...

Title: Re: reactions
Post by: ixi on December 07, 2007, 02:24:12 PM

i found the solution in another p.chem text. thanks for the link though