Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: camariela on April 12, 2006, 11:22:42 PM
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Hello,
I'm confused about the formulas to use and combine to find the moment of inertia and the energy (in kJ/mol) of a nitrogen molecule (N2) in its first excited rotational state.
Thanks
camariela
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What's the equation for moment of inertia?
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I = mr^2
i have the mass, but what do i use for r?
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The radius of a Nitrogen atom I suppose.
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I would rather go for half a triple bond length (or even better for half a N2 length). Atomic radius is for free atom and is of no use here.
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I would rather go for half a triple bond length
I was thinking of rotation down the central axis. Which is the more meaningful?
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Not sure what you mean, but only A variant has any meaning. In B both masses (both nuclei to be precise) lie on the rotation axis and moment of inertia of the particle is zero.
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Yeah, for the B base the only off-axis masses are the electrons and the fact that the nucleus isn't really a point.
Both of these would be some effort to calculcate.
For the A case, the N nuclei masses dominate the calculation, so you can ignore the above complications.
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Both of these would be some effort to calculcate.
Do you have any idea if anybody ever tried to? AFAIR (but QM and spectroscopy were never my favourite subjects) only A was always taken into account. Assuming electron cloud have some moment of inertia changes in rotational energy could be observable in spectroscopy (although probably for wavelengths comparable with astronomical unit :) ).
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Do you have any idea if anybody ever tried to?
Don't know.
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To calculate the moment of inertia of a diatomic molecule, one must use the formula I = mR2, where m is the reduced mass of the molecule (m1m2/m1+m2) and R is the bond length.
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You mean half the bond length?
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Actually, no. R is simply the whole bond length.
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Good to know. :)
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Actually, no. R is simply the whole bond length.
Using the 'reduced mass' takes care of these halves, as well as counting both nuclei.
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I = ? miri2 = m1r12 + m2r22
so we need r1 and r2. They can be found as coordinates of mass center, that are described by conditions:
r1 + r2 = R
m1r1 = m2r2
that gives
r1 = Rm2/(m1+m2)
r2 = Rm1/(m1+m2)
these must be entered into I formula given above, and when rearranged it gives
I = ?R2
quite interesting exercise if you have not done such things in the last 20 years :)
Mitch, did I told you LaTeX will be handy? ;)