Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: abcc on November 11, 2006, 04:45:03 PM
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i have done an experiment which is the bromination of tran-cinnamic acid .
In theoretically , syn & anti- addition both can occur ;
BUT i only got a anti result , what's the reason????
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Brief / revelant explanation is OK :)
THX
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Look up the mechanism, it will become clear.
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Look up the mechanism, it will become clear.
i know the mechanism ,
there is bromonium ion formed :)
thus ,anti is prefered=)
but i still have a question,
what's the difference between the bromination of trans-anethole and trans-cinnamic acid ???
why anethole can have syn-addition ???
actually anethole and cinnamic acid both are quite similar.
Is it because the benzene ring of trans-anethole bond to OCH3,
but trans-cinnamic acid doesn't ???
thx :)
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For syn addition to occur, the bromonium ion must be opened (forming a carbocation) so that the bromide can attack the same face as the first bromine. Anethole has a relatively stable carbocation compared to cinnamic acid. Can you see why?
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For syn addition to occur, the bromonium ion must be opened (forming a carbocation) so that the bromide can attack the same face as the first bromine. Anethole has a relatively stable carbocation compared to cinnamic acid. Can you see why?
I think the reason for the stable carbocation due to the etherbenzene ring, it has resonnance structures that stabilizes the +ive charge (e- donate), is it ???
actually , i am not sure and just guess :)
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I think the reason for the stable carbocation due to the etherbenzene ring, it has resonnance structures that stabilizes the +ive charge (e- donate), is it ???
actually , i am not sure and just guess :)
It's a good guess! Make sure you can draw the resonance structures. This seems like a good explanation to me anyway.
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I think the reason for the stable carbocation due to the etherbenzene ring, it has resonnance structures that stabilizes the +ive charge (e- donate), is it ???
actually , i am not sure and just guess :)
It's a good guess! Make sure you can draw the resonance structures. This seems like a good explanation to me anyway.
is my reason possible???
any other reasons are relevant to explain why??
thx
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I think it is the reason, again, make sure you can draw the resonance structures.
I can't see any other obvious reasons, but that doesn't mean there aren't any.
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I think it is the reason, again, make sure you can draw the resonance structures.
I can't see any other obvious reasons, but that doesn't mean there aren't any.
THE RESONNANC : CH3O=ring=C
The atom O originally has 2 lone pair e-, thus i think it can donate e- to form double bond and stabilize the +ive charge in the ring
is it the possible structure ???
anyway , thx your reply !! :)