Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: nemzy on January 19, 2005, 10:03:57 PM
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1) how many moles of h2 gas should be taken up by 1 octene in the courseof this reaction?
CH3-(CH2)5-CH=CH2 -> (H2PtCl6) -> NaBH4, C2H5OH, HCL -> CH3-(CH2)5-CH2-CH3
Answer is 2 right???
2) What volume does this correspond to at STP?
How can i solve this part?
3) how many moles of molecular hydrogen are consumed per mole of the precatalyst (H2PtCl6) in order to convert it enterily to platinum metal?
Isnt this 2 also?? what is the diff between this and the moles of H2 gas for the question #1?
4) How many moles of precataylst (H2PtCl6) are used in this reaction?
Again is isn't this 2??
My answers don't seem right and i am still a little dubios before submitting them...am i misunderstanding a simple concept here?
thanks
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Each mole of octene needs 1 mole of H2 (one double bond)
H2PtCl6 + 2H2 = Pt + 6HCl
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okies, call me *&^%^$ but what is the difference between 1-octene and n-octene?
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It must be n-octAne, otherwise the question doesn't make sense.
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Octene(s) is more general name for all isomers of C8H16 with one double bond.
1-octene means hydrocarbon with normal chain (unbranched) and double bond at the first carbon atom.
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Yes, but the product must be n-octane.
At least I hope so, or else I really don't understand hydrogenation at all....
:P
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same here, that's what's getting me all confused
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After hydrogenation of 1-octene, 2-octene, 3-octene or 4 octene we can obtain n-octane
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After hydrogenation of 1-octene, 2-octene, 3-octene or 4 octene we can obtain n-octane
Agreed.