Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: 2 Amigos on September 24, 2007, 06:47:39 PM
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Hey there guys, I have this huge assignment for chemistry (47 questions) and I am having trouble with these few. Can anyone help?
What is the mass in grams of 5.9 mol C8H18? (C=12.0amu; H=1.01 amu)
What is the number of moles in 432g Ba(NO3)2? (BA=137.3amu; N=14amu; 0=16amu)
What is the percent composition of Chromium in BaCrO4?
What is the empirical formula of a substance that is 53.5%C, 15.5%H, 31.1%N by weight? (C=12amu; H=1.01amu; N=14amu)
If .89g K and 1.18g Cr react with 1.27g O, what is the empirical formula of the compound? (Molar Masses: K=31.1g; Cr=52G; 0=16g)
Correct name of CoCI2?
When naming a transition metal ion that can have more than one common ionic charge, the numerical value of the charge is indicated by a ______?
Molecular compounds are usually _____?
In Cu2O, the charge of the copper ion is____?
Sodium Nitrade symbol?
Which element combined with fluorine would make an ionic compound?
Pottasium Sulfide symbol?
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What is the mass in grams of 5.9 mol C8H18? (C=12.0amu; H=1.01 amu)
What is the number of moles in 432g Ba(NO3)2? (BA=137.3amu; N=14amu; 0=16amu)
What is the percent composition of Chromium in BaCrO4?
You should start from calculatiom of molecular mass
What is the empirical formula of a substance that is 53.5%C, 15.5%H, 31.1%N by weight? (C=12amu; H=1.01amu; N=14amu)
If .89g K and 1.18g Cr react with 1.27g O, what is the empirical formula of the compound? (Molar Masses: K=31.1g; Cr=52G; 0=16g)
Change masses (percent is a mass in 100 g of compound) to moles of elements, then then find a common multiplier that gives the lowest integer numbers for moles of elements
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When naming a transition metal ion that can have more than one common ionic charge, the numerical value of the charge is indicated by a ______?
Roman numeral
Molecular compounds are usually _____?
Covalent
In Cu2O, the charge of the copper ion is____?
Hint: Oxide is 2-, Cu2O is electrically neutral.