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Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Mr.science on December 20, 2007, 08:34:58 PM

Title: Redox equation balancing (please help me)
Post by: Mr.science on December 20, 2007, 08:34:58 PM
I am having difficulties doing the following redox equation balancing... Please help me

[Cr(N2H4CO)6]4 [Cr(CN)6]3 + MnO4^(-1) --> Cr2O7^(-2) + Mn^(+2) + CO2 + NO3^(-1) (acid)

I don't even know how to break this up into smaller equations...
Any sort of help is appreciated so i can start in the right path!
Title: Re: Redox equation balancing (please help me)
Post by: lutesium on December 21, 2007, 01:07:09 AM
You'd better post this question to the Inorganic Chemistry forum 'cuz I don't think that an Organic Chemist would help you in this question!!!


Lutesium...
Title: Re: Redox equation balancing (please help me)
Post by: AWK on December 21, 2007, 01:16:58 AM
Quote from: lutesium on December 21, 2007, 01:07:09 AM
You'd better post this question to the Inorganic Chemistry forum 'cuz I don't think that an Organic Chemist would help you in this question!!!


Lutesium...
Every chemist should be able to solve redox.
Title: Re: Redox equation balancing (please help me)
Post by: xc on December 21, 2007, 03:36:07 AM
Are you sure the formula for the first compound in your equation is correct? Is it a neutral compound?

N2H4CO is urea, and it's a neutral ligand. CN is cyanide, an anionic ligand (charge -1)

So [Cr(N2H4CO)6]3[Cr(CN)6]3 would make sense: it's just Cr (III).

Check it, please, and I'll try to help you.
Title: Re: Redox equation balancing (please help me)
Post by: Borek on December 21, 2007, 04:07:56 AM
Please read forum rules (http://www.chemicalforums.com/index.php?page=forumrules). Don't crosspost. Topic locked.

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