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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: iluvlost on August 29, 2008, 02:13:52 PM

Title: molarity problem
Post by: iluvlost on August 29, 2008, 02:13:52 PM

What mass of aluminum hydroxide is produced when 50.0 ml of .200 M Al(NO3)3 reacts with 200.0 ml of .100 M KOH?

Al(NO3)3 + 3KOH-> Al(OH)3 + 3KNO3

.05L * .2 M = .01 mol Al(NO3)3
.2L * .1 M = .02 mol KOH

but i dont know where to go from here

Title: Re: molarity problem
Post by: Astrokel on August 29, 2008, 03:01:32 PM

hey iluvlost,

can you determine first the limiting reagent, then the rest will be simple stoichiometry.

Title: Re: molarity problem
Post by: organic_god on August 29, 2008, 09:23:21 PM

looks to me like your aluminium nitrate is in excess/

so basically 3 mols KOH produces 1 mol Aluminium hydroxide
therefore .02 mol KOH produces .02/3 mols of Aluminium hydroxide

mols * molar mass = mass