Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: AE35 on December 05, 2010, 12:07:32 PM
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Hey all!
This is my first post here! :)
I'm trying to lean back into chemistry, but I need some help and explanation that
I hope you can help me with.
I'm to calculate pH in wine that contains 1.72 g monosodium tartrat(E335) per liter.
(pH is only calculated from that salt in the solution)
The molar mass of monosodium tartrat is 172,07 g/mol
I would be very happy if someone could tell me hwo to approach and solve this
problem.
Thanks,
Nicholas
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First step - mass and volume to molarity.
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Well, should I take the 1.72 g and divide by the molar mass:
1.72 g / (172.07 g/mol) = 0.009996 mol ?
...And then divide the moles with the volume(1 L)? This will give M = 0.009996
Thanks! Standing by for advice:)
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Instead of standing by you should be working on calculation pH of the tartrate. Have you checked what it is? Ka values? We can help, but don't expect spoon feeding.
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Do you think you might put a little too much into the 'standing-by' statement?
You really think that I gave the impression that I wanted to be spoon fed? After two
whole posts?
Bye