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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: student33 on June 10, 2011, 07:37:59 PM

Title: Reversible Reactions
Post by: student33 on June 10, 2011, 07:37:59 PM

Hi,

I need help with the integration reversible reactions.
I know that for a reversible reaction where A <-> C (forward reaction has a rate constant of k₁ and the reverse reaction has a rate constant of k_-1), the reaction rates are:

d[A]/dt = -k₁[A] + k_-1[C]

and

d[C]/dt = k₁[A] - k_-1[C]

If the initial condition is that [A]_o = [A] + [C]

Then,

d[A]/dt = -k₁[A] + k_-1([A]_o-[A])

I don't get how the integration of this equation will give me:

[A] = [Ao] (k_-1 + k₁e^{-(k₁-k_-1)t})/(k₁ + k_-1)

Any help will be appreciated.

Title: Re: Reversible Reactions
Post by: Jorriss on June 11, 2011, 02:18:22 AM

http://integral-table.com/

Title: Re: Reversible Reactions
Post by: slavinzing56 on July 04, 2011, 04:12:28 AM

Jorriss  : Wow thanks!