Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Steenrod on October 19, 2012, 02:26:11 AM
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What are the products formed by reductive ozonolysis of penta-1,3-diene?It seems the two double bonds are confusing me.Thanks.
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Complete reductive ozonolysis should give methanol, ethanol and ethylene diol.
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Can you please explain how you arrived at the answer?
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What does ozonolysis do to a double bond, and what does the reductive work-up do?
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ethylene diol
Do you mean ethane-1,2-diol or ethylene glycol?
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The first one.
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@Steenrod
Have a read at this page:
http://www.ch.ic.ac.uk/local/organic/18.html (http://www.ch.ic.ac.uk/local/organic/18.html)
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Both are the same, only ethylene diol is not known.
If existing, it would be HOCH=CHOH, what converts to OHC-CHO Ethane-dial (Glyoxale).
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It is a reductive ozonoylsis, that means the aldehydes and ketones produced are reduced to the corresponding alcohols.
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Thats correct, but I was talking about the name ethylene diole. Not about the ozonolysis.
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Sorry, I was not clear what you meant.
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I would have suggested different products. I always thought that ozonolysis had and oxidative (H+, H2O2) or reductive (Me2S or Zn, HOAc) work up. If that were the reductive work up, then aldehydes would be the products, formaldehyde, glyoxal, and acetaldehyde.
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If that's the case here then I agree with your suggested products.