Chemical Forums
Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: DannyBoi on February 04, 2013, 05:39:36 PM
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Hi, I would like to know why I am always getting the incorrect answer when I input it into these online drill exercises:
http://mmotif.concordia.ca/teaching/
When I do the exercises for extracting rate constants from second-order reactions, I use the integrated rate law:
k = (1/[A]t - 1/[A]0) * 1/t
And after converting to the correct units, my answer is always exactly double the value of the "correct" answer. Can anyone say what the error is?
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$$v=k[C]^{2}=-\frac{1}{2}\frac{d[C]}{dt}$$
remember:
$$aA\rightarrow pP$$
$$v=k[A]^{a}=-\frac{1}{a}\frac{d[A]}{dt}=\frac{1}{p}\frac{d[P]}{dt}$$