Chemical Forums
Chemistry Forums for Students => High School Chemistry Forum => Topic started by: Rutherford on March 01, 2013, 10:37:10 AM
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Problem: When saying ''the solution of carbonic acid'', it is actually meant "the solution of carbon-dioxide in water". Most often, the pKa1 of this acid is said to be 6.4, which is not expected from its structure. If you know that in a soda-water, whose pH is 5.65, only 0.2% of the dissolved carbon-dioxide is present in the form of the undissociated acid, how much is the real first constant of acidity of H2CO3?
Attempt: I mark the number of moles of the dissolved CO2 at the beginning with x. 0.002x is the number of moles of carbonic acid. I have two reactions:
1° CO2+H2O ::equil:: HCO3- + H+ pKa1=6.4
0.998x y 2.24*10-6
y=0.177x
2° H2CO3 ::equil:: HCO3- + H+ pKa1=z
0.002x 0.177x 2.24*10-6
z=3.70 while the answer is 3.77. Where am I wrong?
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1° CO2+H2O ::equil:: HCO3- + H+ pKa1=6.4
0.998x y 2.24*10-6
Why 0.998x? pKa=6.4 was calculated assuming there is NO free CO2 present.
I would start calculating total concentration of carbon dioxide from known pH and pKa (assuming it is 100% converted into carbonic acid).
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How do you mean NO CO2? The first pKa was calculated assuming that this reaction represents carbonic acid:
CO2+H2O ::equil:: HCO3-+H+
"I would start calculating total concentration of carbon dioxide from known pH and pKa (assuming it is 100% converted into carbonic acid)."
How would I do that? I need the concentration of HCO3-?
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How do you mean NO CO2? The first pKa was calculated assuming that this reaction represents carbonic acid:
CO2+H2O ::equil:: HCO3-+H+
No FREE CO2. All is present in the form of H2CO3, and the reaction taking place is
H2CO3 ::equil:: H+ + HCO3-
Thats the definition of Ka, isn't it?
How would I do that? I need the concentration of HCO3-?
Stoichiometry of dissociation.
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No FREE CO2. All is present in the form of H2CO3, and the reaction taking place is
H2CO3 ::equil:: H+ + HCO3-
I calculated H2CO3 when assumed that [H+]=[HCO3-] then the actual [H2CO3]=0.002*the one I calculated earlier. Then again, I get the same pKa, 3.7 ???.
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Wording is slightly ambiguous. I took
only 0.2% of the dissolved carbon-dioxide is present in the form of the undissociated acid
to mean 0.2% of the carbon dioxide is converted to carbonic acid (and dissociation follows), while it is intended to mean "in the equilibrium mixture concentration of carbonic acid is 0.2% of the total analytical concentration of CO2".
And with this approach I got 3.77.
Which is kind of stupid - final answer is given with three sigfigs, while the least number of sigfigs in the input data is one.
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Got the same.
Calculated the concentration of CO2 from the first reaction, then added the amount that dissociated (2.24*10-6) to get the analytical concentration and I multiplied it by 0.002 to get the concentration of carbonic acid. Then the answer is really 3.77.
Thanks for the help.