Chemical Forums
Chemistry Forums for Students => Organic Chemistry Forum => Topic started by: Brook on July 23, 2013, 01:16:23 AM
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If I have a molecule like the one shown, is it antiaromatic because it does not satisfy Huckle's Rule; it only has 4 pi electrons?
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My apologies for the extremely large picture.
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It is actually going to be aromatic because the oxygen is sp2 hybridized. One of the lone pairs on oxygen is in a p orbital. So the number of pi electrons is actually 6. The molecule is planar , and has continous circle of p orbitals. So all conditions satisfied, it will be aromatic.
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Yep, aromatic. I typically test student for both aromaticity and resonance at the same time via questions just like this. I would suggest getting more of these examples. If not available, ask your professor to assign "extra problems for the class."