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Chemistry Forums for Students => High School Chemistry Forum => Topic started by: maleme on October 06, 2013, 09:03:23 PM

Title: H2O Mol Equivalency
Post by: maleme on October 06, 2013, 09:03:23 PM

I'm new to chemistry, doing research, trying to replicate a study, and I don't understand the H2O mol equivalency in the following example.

EXAMPLE: 1.375 g (0.0028 mol) of N3300A was dissolved in 94 mL of dry acetone, 1.5 mol equivalents of water (0.073 mL, 0.0042 mol) was added on top.

I'm trying to substitute the 1.375 g (0.0028 mol) of N3300A with a different monomer, and use the same 1.5 mol equivalents of water (0.073 mL, 0.0042 mol).

How do I calculate the amount of the different monomer I need?

Kind Regards

Title: Re: H2O Mol Equivalency
Post by: magician4 on October 06, 2013, 09:17:44 PM

you need to know the (average) molecular weight M of the replacement, so you can calculate the respective moles n from the mass m : . n = m/M


regards

Ingo