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Chemistry Forums for Students => Physical Chemistry Forum => Topic started by: san1984 on April 17, 2006, 07:33:11 AM

Title: Need help on integrated rate law
Post by: san1984 on April 17, 2006, 07:33:11 AM
Hi,

please advise me on the computation for integrated rate law for this reaction :

A + B ---> product

we start from -d[A]/dt = k[A]

I ended up with ln([A]/[A]oo) = - kt
but I think there is something wrong in my integration. Please help. Thanks !

Title: Re: Need help on integrated rate law
Post by: Albert on April 17, 2006, 07:49:01 AM
The correct integrated form is:

1/(°-[A]°) * ln (*[A]°)/([A]*°)  = kt
Title: Re: Need help on integrated rate law
Post by: Winga on April 17, 2006, 08:32:45 AM
Let [A] = [A]o - x and = o - x,

d[A]/dt = -k([A]o - x)(o - x)

d[A]/dt = -dx/dt

dx/dt = k([A]o - x)(o - x)

Int. dx/([A]o - x)(o - x) = Int. kdt
Title: Re: Need help on integrated rate law
Post by: san1984 on April 17, 2006, 09:49:08 AM
oic ... Thanks for the prompt reply and great help !! :)