[Nori]

I'm having a lot of trouble with this for some reason, can someone give me some hint or step to solve this?

When 2.36 moles of iron iii bromide yields 6.14 moles of sodium bromide, what is the percentage yield of the sodium bromide?

2FeB₃+3Na₂S --> Fe₂S₃+6NaBr

What I did was convert the moles into g and I don't know what to do next

[AWK]

FeB₃ - printing error

What I did was convert the moles into g

You can make calculations with moles.
How many moles of NaBr should be formed from 2.36 moles of iron(III) bromide - this is a theoretical yield.

[Vidya]

What I did was convert the moles into g and I don't know what to do next

Calculate moles formed as suggested by AWK and take ratio of moles formed with theoretical moles multiplied by 100%. No need of converting in grams.