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Freezing point depression
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Topic: Freezing point depression (Read 3911 times)
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uzi4u2
Regular Member
Posts: 33
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Freezing point depression
«
on:
August 22, 2006, 10:36:57 AM »
okay so this is the question :
0.15g urea ( molar mass 60 delton ) is dissolved in 25g water . what is the freezing point depression of the solution ? the molal freezing point Kf of water is 1.85
now the formula is dT=Kf*C*I
so what i did was 0.15/60 in order to get the number of moles in 1000g
this gave me 2.5x10-3 but this is in 1000g so i need it in 25g so
2.5x10-3 ... 1000
x.... 25
x= 6.25x10-3
and now i take this and put it in the formula instead of C but it dosent come out good :\
any ideas on what i am doing wrong ?
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Yggdrasil
Retired Staff
Sr. Member
Posts: 3215
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Physical Biochemist
Re: Freezing point depression
«
Reply #1 on:
August 22, 2006, 12:56:41 PM »
To calculate the concentration, you need to figure out the number of moles then divide that by the volume of your solution, so its:
0.15g / 60 g/mol = 2.5x10
-3
mol (you did this correctly) but,
concentration = 2.5x10
-3
mol / 25g
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uzi4u2
Regular Member
Posts: 33
Mole Snacks: +0/-1
Re: Freezing point depression
«
Reply #2 on:
August 22, 2006, 01:07:50 PM »
oo i see so it will be x/25*1000 and what i will get from it i will put in the equation ! great
thanks
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Freezing point depression