[Romenumeral]

What s the Density of  a solution that has  H2SO4 concentration 95.72% and 17.91M?

[Borek]

Just google density tables for the sulfuric acid.

[Romenumeral]

Just google density tables for the sulfuric acid.

But how do i solve it without? Can you help me please?

[INeedSerotonin]

We can find it with molarity = moles / volume, and concentration = mass / volume.

So let's replace "moles" with "mass" over "molar mass".

molarity = mass / (molar mass . volume). But mass / volume = density. So molarity = density over molar mass.

Replace everything and you will find 1.75 g / mL or 1.75 g / cm^3

But I'm just a beginner. I'm not sure this is right. Perhaps somebody better than I in chemistry can correct me.

[Romenumeral]

We can find it with molarity = moles / volume, and concentration = mass / volume.

So let's replace "moles" with "mass" over "molar mass".

molarity = mass / (molar mass . volume). But mass / volume = density. So molarity = density over volume.

Replace everything and you will find 1.75 g / mL or 1.75 g / cm^3

Sorry for directly giving you the answer. I didn't know how to guide you to the answer here.

Concentration isn t dissolved mass over mass of the solution?

[AWK]

Use the definition of percent concentration
p=(m_solute/m_solution)*100
When using mass of 17.91 moles of sulfuric acid you will obtain m-solution will be the volume of 1-liter od 95.71 % of acid. Then you can use definition of density in the simplest way.

[INeedSerotonin]

We can find it with molarity = moles / volume, and concentration = mass / volume.

So let's replace "moles" with "mass" over "molar mass".

molarity = mass / (molar mass . volume). But mass / volume = density. So molarity = density over volume.

Replace everything and you will find 1.75 g / mL or 1.75 g / cm^3

Sorry for directly giving you the answer. I didn't know how to guide you to the answer here.

Concentration isn t dissolved mass over mass of the solution?

I always learnt it as mass / volume. Many classmates of mine would always mistake it for density, because the formulae are practically the same.

[mjc123]

We can find it with molarity = moles / volume, and concentration = mass / volume.

So let's replace "moles" with "mass" over "molar mass".

molarity = mass / (molar mass . volume). But mass / volume = density. So molarity = density over molar mass.

This is a classic case of confusing yourself by using the same word with different meanings.
molarity  = moles solute/mass of solution;  concentration is mass of solute /mass of solution
molarity = (mass solute/molar mass)/volume of solution = concentration/molar mass. Density is not involved.
Density of solution = mass of solution/volume of solution

[Romenumeral]

We can find it with molarity = moles / volume, and concentration = mass / volume.

So let's replace "moles" with "mass" over "molar mass".

molarity = mass / (molar mass . volume). But mass / volume = density. So molarity = density over volume.

Replace everything and you will find 1.75 g / mL or 1.75 g / cm^3

Sorry for directly giving you the answer. I didn't know how to guide you to the answer here.

Concentration isn t dissolved mass over mass of the solution?

I always learnt it as mass / volume. Many classmates of mine would always mistake it for density, because the formulae are practically the same.

What you said i think it os volume percent and what i say is mass percent,bit i gigured it out thank you guys.Answer is 1.83

[INeedSerotonin]

Can you show us how you found the answer?