Yes (theoretically) and no (practically). The solubility of Ag
2S in water is of ~10
-15 M. OH
- ion concentration in pure water is of ~10
-7 M. At this concentration of sulfide ion it will almost completely hydrolyze to H
2S and trace amounts of HS
- ions (note - trace in relation to the concentration of 10
-15 M). In this case, the voltage could be adjusted so that the water will not undergo electrolysis. But the extremely low current caused by the ionic conductivity of water will be even thousands of times greater than that used for the electrolytic decomposition of AgOH and AgHS. Rather, certainly no one tried to obtain metallic silver by this method, but e.g. by the electrolysis of molten Sb
2S
3, the elemental Sb is obtained.
Does it mean that Ag+ will gain one electron and become metallic Ag, and 8 moles of ion sulphur will lose two electrons...
One Ag
+ ion corresponds to 1/2 sulfur atom, and this corresponds to 1/16 of the S
8 molecule.