[JayShah]

The volume of a certain liquid varies with temperature as V=V`{0.77 + 3.7 x 10^(-4)(T/K) + 1.52 x 10^(-6)(T/K)^2} where V` is its volume at 298K. Calculate its expansion coefficient, alpha, at 310K.

How am I to go about doing this problem?
alpha is  = (1/V)(dv/dt)_p

[curiouscat]

First, find that derivative.

[JayShah]

First, find that derivative.

Derivative of the equation given? Is the T a variable. After I take the derivative then what do I do? In respect to what variable do I take this derivative?

[curiouscat]

dV/dT

[JayShah]

Wow that was stupid easy. Thank you!

[AWK]

Wow that was stupid easy. Thank you!

If you write the formula correctly