[demvp_demar]

Hello, We are having a lab tomorrow and I am preparing for it. We will be given 6 unidentified solutions and we will be tasked with identifying them by mixing and observing.

The 6 solutions are:

1. CuSO4 (Colour is blue)

2. Cu(NO3)2 (Colour is blue)

3. BaCl2

4. Na2CO3

5. (NH4)2SO4

6. ZnSO4

It will be easy to identify CuSO4, Cu(NO3)2, BaCl2 and Na2CO3. Since both BaCl2, and Na2CO3 will form a participate with CuSO4. While only Na2CO3 will form a participate with  Cu(NO3)2.


But how will I be able to distinguish between ZnSO4 and (NH4)2SO4 since neither reacts with the copper solution?

[chenbeier]

But how will I be able to distinguish between ZnSO4 and (NH4)2SO4 since neither reacts with the copper solution?

Think about  what happens to Ammonium getting alcaline. Which solution can be used?

While only Na2CO3 will form a participate with  Cu(NO3)2.

This is wrong, Barium and Zink will also do a precipitate.