In lab, students collect 42.6mL of N2 gas over water 24 C and 751 torr. The water in the eudiometer is 16.5 cm higher than the water outside.
Calculate the dry standard volume of N2
" The water in the eudiometer is 16.5 cm higher than the water outside. "
this sentence brings all the confusion, does someone has a picture that explains it? does it mean that the atmospheric pressure is higher by 16.5cm water, then i convert that to mmHg.
hence
PN2=Patm-P(difference)-Pwater
and then
PV=nRT
V=nRT/P
but still i have no moles, any hints?