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Topic: How to make 1g of K0.5Bi0.5TiO3  (Read 1773 times)

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Offline nqm

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How to make 1g of K0.5Bi0.5TiO3
« on: November 11, 2020, 10:34:59 AM »
From starting materials K2CO3, BiO2, TiO2
What is the balanced equation as well?

Any help would be greatly appreciated
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Offline chenbeier

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Re: How to make 1g of K0.5Bi0.5TiO3
« Reply #1 on: November 11, 2020, 11:39:38 AM »
Strange Formula.

1. Get the molar mass of it.
2. Calculate the mole for 1 g.
3. From the given educts, calculate their moles.
4. Develop the balanced equation.

I think BiO2 should be Bi2O3

Now it is your work.
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Offline nqm

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How to make 1g of Mg-doped 2 at% (at the Ti-site) K0.5Bi0.49Ti0.98Mg0.02O2.965
« Reply #2 on: November 24, 2020, 07:16:23 AM »
I started the experiment by making K0.5Bi0.5TiO3, with equation K2CO3 + Bi2O3 + TiO2 = 4K0.5Bi0.5TiO3 + CO2.
Now I need to dope Mg into the Ti site and am unsure on how to proceed. What chemical equations/stoichiometric equivalents will I need?

Thanks
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Offline AWK

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Re: How to make 1g of Mg-doped 2 at% (at the Ti-site) K0.5Bi0.49Ti0.98Mg0.02O2.965
« Reply #3 on: November 24, 2020, 08:01:54 AM »
This modified perovskite was obtained 7 years ago. Do you read original literature? And the rest is stoichiometry. chenbeier recently told you how to do this.
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AWK

Offline billnotgatez

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Re: How to make 1g of K0.5Bi0.5TiO3
« Reply #4 on: November 24, 2020, 12:17:00 PM »
@nqm
I have merged all your posts on this topic

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