"The total oxidation of glucose occurs according to the following chemical equation:
C6H12O6 (s) + 6O2 (g) -> 6CO2 (g) + 6H2O (l)
The table gives us the free energies of standard formation and the standard molar entropies of compounds involved in the previous reaction.
| Compound | ∆fG° (298K) kJ/mol | S°m (298K) J/K/mol |
|-------------|-------------------------|------------------------|
|C6H12O6 | -917,2 | 212,10 |
| O2 | 0 | 205,14 |
| CO2 | -394,36 | 213,74 |
| H2O | -273,13 | 69,91 |
Based on the table data, determine the ∆rGº for glucose oxidation at 308 K"
Guiven:
R = 8,314 J K-1 mol-1
∆rG = ∆rG°+RT 𝑙𝑛 Q
ln 𝐾2 = ln 𝐾1 −∆rH°/ 𝑅 (1/𝑇1−1/𝑇2)
I calculated ∆rH° and I want to know if I need to use any of the guiven formula or if i can use ∆rG = ∆rH - T∆rS to calculate ∆rG considering ∆rH and ∆rS as constant.