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Offline Amrik

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Question About Solids
« on: October 09, 2006, 07:19:46 AM »
I am stuck a bit with this question
The body centered cubic cell of iron has a length of 0.286 nm. Calculate the density of iron (g/cm^3).

how should i do it? i did it this way
mass = 55.8g/mol  * 1 mol/6.022x10^-23 = 9.266x10^-23g x 2ions/ 1 ion = 1.853x10^-23 g

volume = (0.286 x 10^-7cm)^3 = 2.339 x 10^-23 cm^3

denisty = 1.853 x 10^-23 g / 2.399 x 10^ - 23 cm^3 = 7.922 g/cm^3

is it correct? well i got  0.5/1 (or) 2 i just cannot remember

Offline Dan

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Re: Question About Solids
« Reply #1 on: October 09, 2006, 08:35:31 AM »
I am stuck a bit with this question
The body centered cubic cell of iron has a length of 0.286 nm. Calculate the density of iron (g/cm^3).

how should i do it? i did it this way
mass = 55.8g/mol  * 1 mol/6.022x10^-23 = 9.266x10^-23g x 2ions/ 1 ion = 1.853x10^-23 g

volume = (0.286 x 10^-7cm)^3 = 2.339 x 10^-23 cm^3

denisty = 1.853 x 10^-23 g / 2.399 x 10^ - 23 cm^3 = 7.922 g/cm^3

is it correct? well i got  0.5/1 (or) 2 i just cannot remember

I think you are out by a power of 10 in right hand side the highlighted bits. However, you are out by a factor of ten one way in one calculation, and the other way in the other, so your errors have cancelled.
Apart from that, I think it is right.
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Offline Amrik

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Re: Question About Solids
« Reply #2 on: October 10, 2006, 01:20:07 AM »
Out by a power of 10...can you explain that a bit more Dan  :( I did it the exact same way how they did it in here Chemistry
in the website you scroll down a bit and their will be ">> Explore: Unit Cell Tutorial " that is where i got it from

2 more questions please :P

Q1. An arrangement in which every other layer is identical (ABABABAB) is :
a) Octahedral Holes
b) Tetrahedral holes
c) hexagonal close packing
d) cubic close packing

Ans - is it (c) hexagonal close packing?

2. A crystal that does not conduct electricity, even after melting. It is hard and brittle, it melts at a very high temperature. What type of a crystal is it?

Ans - it is a covalent network crystal right?
« Last Edit: October 10, 2006, 01:34:47 AM by Amrik »

Offline english

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Re: Question About Solids
« Reply #3 on: October 10, 2006, 02:46:43 AM »
I am stuck a bit with this question
The body centered cubic cell of iron has a length of 0.286 nm. Calculate the density of iron (g/cm^3).

how should i do it? i did it this way
mass = 55.8g/mol  * 1 mol/6.022x10^-23 = 9.266x10^-23g x 2ions/ 1 ion = 1.853x10^-23 g

1 mol of iron is 6.022 x 1023 ions. 

Also, 0.286 nm = 2.86 x 10-12cm

« Last Edit: October 10, 2006, 02:53:01 AM by k.V. »

Offline Borek

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Re: Question About Solids
« Reply #4 on: October 10, 2006, 03:00:00 AM »
1 mol of iron is 6.022 x 1023 ions.

More likely atoms in this case.

Quote
Also, 0.286 nm = 2.86 x 10-12cm

huh?

1 nm = 10-9m

1 cm = 10-2m
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Offline english

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Re: Question About Solids
« Reply #5 on: October 10, 2006, 03:12:36 AM »
1 mol of iron is 6.022 x 1023 ions.

More likely atoms in this case.

Quote
Also, 0.286 nm = 2.86 x 10-12cm

huh?

1 nm = 10-9m

1 cm = 10-2m

I meant 1 x 10-8 cm

He was right originally I didn't see that  :-\

Offline Dan

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Re: Question About Solids
« Reply #6 on: October 10, 2006, 03:13:42 AM »
I am stuck a bit with this question
The body centered cubic cell of iron has a length of 0.286 nm. Calculate the density of iron (g/cm^3).

how should i do it? i did it this way
mass = 55.8g/mol  * 1 mol/6.022x10^-23 = 9.266x10^-23g x 2ions/ 1 ion = 1.853x10^-23 g

Should be

mass of iron atom = 55.8 / 6.022x10+23 = 9.266x10-23g
mass of two iron atoms = 1.853x10-22

Quote
volume = (0.286 x 10^-7cm)^3 = 2.339 x 10^-23 cm^3
correct

Quote
denisty = 1.853 x 10^-23 g / 2.399 x 10^ - 23 cm^3 = 7.922 g/cm^3

denisty = 1.853 x 10-22 / 2.399 x 10-23 = 7.922 g/cm^3

so your answer is correct, but your working is not quite right
My research: Google Scholar and Researchgate

Offline Borek

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Re: Question About Solids
« Reply #7 on: October 10, 2006, 04:19:40 AM »
Quote
Quote
Also, 0.286 nm = 2.86 x 10-12cm

huh?

1 nm = 10-9m

1 cm = 10-2m

I meant 1 x 10-8 cm

Even with -8 you will be still wrong  :P
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Offline Dan

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Re: Question About Solids
« Reply #8 on: October 10, 2006, 07:48:41 AM »
Even with -8 you will be still wrong  :P

No, he'd be right, 0.286 x10 -7 = 2.86 x10 -8

My research: Google Scholar and Researchgate

Offline Amrik

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Re: Question About Solids
« Reply #9 on: October 10, 2006, 09:06:29 AM »
I am stuck a bit with this question
The body centered cubic cell of iron has a length of 0.286 nm. Calculate the density of iron (g/cm^3).

how should i do it? i did it this way
mass = 55.8g/mol  * 1 mol/6.022x10^-23 = 9.266x10^-23g x 2ions/ 1 ion = 1.853x10^-23 g

Should be

mass of iron atom = 55.8 / 6.022x10+23 = 9.266x10-23g
mass of two iron atoms = 1.853x10-22

Quote
volume = (0.286 x 10^-7cm)^3 = 2.339 x 10^-23 cm^3
correct

Quote
denisty = 1.853 x 10^-23 g / 2.399 x 10^ - 23 cm^3 = 7.922 g/cm^3

denisty = 1.853 x 10-22 / 2.399 x 10-23 = 7.922 g/cm^3

so your answer is correct, but your working is not quite right

Quote
ok i know now that i was wrong about this "mass of two iron atoms = 1.853x10-22"

but this one
Quote
mass of iron atom = 55.8 / 6.022x10+23 = 9.266x10-23g
if i divide it using +23 how can i get an answer with the power -23?...I tried doing it with my calculator i get a power of +23 not -23

Offline Dan

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Re: Question About Solids
« Reply #10 on: October 10, 2006, 02:56:46 PM »
you must be inputting it wrong. Put brackets around 6.022 x10 23

Note that dividing by 1023 is the same as multiplying by 10-23
My research: Google Scholar and Researchgate

Offline Amrik

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Re: Question About Solids
« Reply #11 on: October 11, 2006, 01:33:07 AM »
 :-\ yeah...i did really input it the wrong way!
Thanks alot for the help Dan!.

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