@rolnor
The electron beam appears straight in the sense that you know where the beam is produced and you can draw a straight line between it and your target. But the beam is not perfectly collimated.
I thought to make an argument based on beam divergence angles. A laser (which shapes light by matter-based optics) has a beam divergence based on fundamental properties of light; a typical green laser pointer has divergence typically on the order of about a milliradian, or ~0.05 deg. See for example
this one by Edmund Optics. All particle beams have divergence, not just lasers. I’m no expert but here’s an example of a
divergence angle measurement on an electron beam (Kim et al 2020 Nuclear Inst. Methods Phys. A, 953, 163054): they measured approx. 2 deg. That’s several orders of magnitude higher divergence in a high-powered electron beam than an inexpensive laser pointer. I found similar values for some positively charged ion beams, e.g.
here (Pai and Venkatramani, Rev Sci Inst. 1992, 63, 5234).
Now I have to stop and give you a big sarcastic thank you, rolnor. It was about this point I got lost for three hours reading about the physics of charged particle beams. At first I assume the large divergence in electron beams was due to simple Coulomb repulsion; squeaky clean argument. But (no surprise) it seems to be due to much more goofy quantum s#*$ than that. The article I linked to on electron beam divergence angles attributed the divergence to the property called ‘emittance’. So I looked that up and got thoroughly shot down the rabbit hole like I was fired from (ha) an electron gun. If you don't believe me, just google "particle beam emittance". Yikes. Anyway, long story short, the equations for transverse momentum components of the high energy beam emittance do indeed contain a factor proportional to the particle charge (
example, but don't say I didn't warn you), so … yeah... I guess I was kind of right. Even though it hardly feels like a victory 😉.