September 16, 2024, 04:23:27 PM
Forum Rules: Read This Before Posting


Topic: Equilibrium problem  (Read 3970 times)

0 Members and 1 Guest are viewing this topic.

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2271
  • Mole Snacks: +185/-49
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: Equilibrium problem
« Reply #15 on: February 15, 2024, 06:09:15 PM »
No , it is the square root of 0.218 not the second Power.
I you have a reaction

A => B + 0.5 C

Then K = B* sqr(C)/ A

So let say 40% decompose of 0,8

Then K = 0,32*sqr(0,16)/0,48

Offline bmcevoy1776

  • Regular Member
  • ***
  • Posts: 10
  • Mole Snacks: +0/-0
Re: Equilibrium problem
« Reply #16 on: February 15, 2024, 06:15:32 PM »
its my typo. but i assure you its raised to the stochiometric coefficient. the 1st problem was 2. but the question with the pictures is the 1/2 power. that's the theorem. but the question is why is it being raised to the co efficient twice. all the problems raises it to the coefficients power  twice

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2271
  • Mole Snacks: +185/-49
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: Equilibrium problem
« Reply #17 on: February 15, 2024, 06:28:21 PM »

Offline bmcevoy1776

  • Regular Member
  • ***
  • Posts: 10
  • Mole Snacks: +0/-0
Re: Equilibrium problem
« Reply #18 on: February 15, 2024, 06:57:59 PM »
all this tells me is khan academy sucks. no 1 has told me yes its correct & here is why, or no khan academy sucks at chemistry its not the correct answer. but chat gpt did the same thing without being prompted. was the other 1 raised to its coefficient twice as well but since its 1 it equals the original ??

Offline Hunter2

  • Sr. Member
  • *****
  • Posts: 2271
  • Mole Snacks: +185/-49
  • Gender: Male
  • Vena Lausa moris pax drux bis totis
Re: Equilibrium problem
« Reply #19 on: February 16, 2024, 01:54:22 AM »
I realy don't get what you are talking about. Show the problem you not understand.

In the law of mass Action the stoichometric coefficients go as exponent.


2A => 3 B  K = B^3/A^2 for example.
« Last Edit: February 16, 2024, 02:04:44 AM by Hunter2 »

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27785
  • Mole Snacks: +1805/-411
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Equilibrium problem
« Reply #20 on: February 16, 2024, 03:41:58 AM »
I am starting to wonder if when OP writes "squared" it doesn't sometimes mean "multiplied by 2" and sometimes "squared".

in this example .436 raised to the 1/2 power is .218

0.218 is half of 0.436, not square root of 0.436 (which is 0.466)

Quote
but they show .218 raised to the 1/2 power again in the final theorem

For some reason we probably don't see what you see, but perhaps what is really happening is they multiply by a stoichiometric coefficient to calculate amount in the first stage (just applying simple stoichiometry), then use the stoichiometric coefficient in the K formula to raise the concentration to the second power. So it is not "squaring" twice, it is multiplying and then squaring in two different stages of solving the problem: follow the stoichiometry first, plug into K formula second.

Quote
not my fault they explain it like assholes. this would be raising it to the stoichiometric coefficient 2 different times.

Please calm down, blaming everyone around won't get you far.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links