How many grams of ZnBr2 would be produced by the complete reation of 12.4g of Zn with HBr according to the following equation?
Zn + 2HBr > H2 + ZnBr2
So far I got:
12.4gZn x 1mol Zn x 1mol ZnBR2 x 225.19g ZnBr2
---------------------------------------------- = 2792.36
65.39g Zn x 1 mol Zn x 1 mol ---------- = 42.70g ZnBr2
65.39
IS ThIS RIGHT???