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Topic: Balancing equation...  (Read 4233 times)

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Offline pin0y

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Balancing equation...
« on: October 31, 2006, 09:58:28 PM »
ahhh this is driving me crazy...
is it possible to balance this equation:? if so, what r the coefficients?

FeC2O4*2H2O + H2C2O4 + H2O2 + K2C2O4 ---> K4[ Fe(C2O4)4 ] * 3H2O

thank you

Offline enahs

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Re: Balancing equation...
« Reply #1 on: October 31, 2006, 10:10:22 PM »
Is that product perhaps supposed to be K3[Fe(C2O4)3] . 3 H2O

And the answer to your question is I believe no, perhaps I set it up wrong but using the algebraic method I get negative coefficients required, which is not valid.
« Last Edit: October 31, 2006, 10:36:08 PM by enahs »

Offline pin0y

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Re: Balancing equation...
« Reply #2 on: October 31, 2006, 11:25:26 PM »
yea the subscripts for H2O and K and C2O4 were obtained from our experiment so i guess my results ended up for an impossible to balance equation... which i was just trying to check to make sure that it wasn't possible to balance...
thx

Offline Borek

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Re: Balancing equation...
« Reply #3 on: November 01, 2006, 03:14:54 AM »
Your reaction still can be balanced, but you have to play a little bit with water:

FeC2O4 + H2C2O4 + H2O2 + 2K2C2O4 -> K4[Fe(C2O4)4] + 2H2O

So, assuming that's the basic chemistry taking place (I suppose it was done in water, wasn't it?) all you have to do now is to balance crystallization water - you may safely add it and/or substract on both sides of the equation.

FeC2O4.2H2O + H2C2O4 + H2O2 + 2K2C2O4 -> K4[Fe(C2O4)4].3H2O + H2O

But Shane is right - you formula doesn't look convincing.
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