December 23, 2024, 08:49:56 AM
Forum Rules: Read This Before Posting


Topic: Hess's Law  (Read 2763 times)

0 Members and 1 Guest are viewing this topic.

Offline enantiomorph

  • Regular Member
  • ***
  • Posts: 13
  • Mole Snacks: +0/-0
Hess's Law
« on: November 03, 2006, 03:47:08 AM »
Hi, I was working on some questions involving thermochemistry.  I came across a problem involving heats and enthalpy that I don't know how to solve.  I was wondering if anyone may please give me a hand with this.  Thank You.

Question:  How much heat is evolved when 1.022x10 moles of CO2(g) is produced from the combustion of CO(g).
2CO(g) + O2(g) -> 2CO2(g)
The enthalpies of formations are:
CO(g) -110.5 kJ/mol
O2(g) 0.0
CO2(g) -393.5 kJ/mol
H2O(l) -286.0 kJ/mol

I tried the problem and I applied the formula for findng enthalpies with the enthalpies of formation [i.e. (Sum of # moles x enthalpy of formation for products) - (Sum of # moles x enthalpy of formation for reactants)]
I got a value of -566 kJ/2mol so -283 kJ/mol, then I multiplied 10.22 mol to -283 kJ/mol, but the answer was wrong according to my book.  If someone can help, that will be great.  Thanks alot.

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7976
  • Mole Snacks: +555/-93
  • Gender: Male
Re: Hess's Law
« Reply #1 on: November 03, 2006, 09:04:58 AM »
AWK

Sponsored Links