oh allright I just got a bit confused. what you said is right.
hybridization of one s, two p, and one d orbital on a central metal atom gives rise to four hybrid dsp2 orbitals. They are square planar in alignment because the orbitals used are all in the xy plane. in d2sp3 hybridisation, the orbitals which contribute to the square planar geometry of the equatorial plane of the octahedron are the s, px, py, and dxy atomic orbitals. is my understanding correct?
thanks