Hi!
Right, where to begin...
An mp of 172C is quite high, implying H-bonding, but the nmr doesn't seem to support this conclusively.
Is the H-NMR run in CDCl3? Because that would explain your peak at 7.28 - residual CHCl3 peak.
About your MS... what ionisation was it? I'm assuming EI or ESI, but do you have Na+ or K+ present? because you might be observing [M+Na] or [M+K] in addition to your [M+H] peak.
With regards to Chiralic...
NMR: Absorption 7.281 (single peak) must be considered:
- Possibility of aromatic proton or
- groups of CHO, OH, COOH
aldehyde protons tend to exhibit around 9-10ppm
COOH protons are anywhere between 10-12ppm depending on solvent.
If the nmr solvent is able to exchange protons with any of these, you shouldn't observe them.
And OH protons in alcohols are around 5ppm.
Also:
The splitting on:
- 3.4 (doublet) must be: (CH3)2CH group or CH3CH group
- 3.5 ; 3.7 (triplet) must be: C2H5 group or CH3CH2CH2 group
If your NMR data is complete, then (CH3)2CH and CH3CH-R2 are unlikely as you would observe a doublet/septet and doublet/quartet respectively.
It's an interesting question, a little more info would probably sort things out.
Happy reactions,
mib