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Topic: Molecular Geometry  (Read 15644 times)

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Offline saN

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Molecular Geometry
« on: December 02, 2006, 12:53:44 AM »
I think that the molecular geometry for the hydrocarbon butane (C4H10) at each of the carbons atoms is tetrahedral for both isomers. Am I correct?
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Offline Yggdrasil

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Re: Molecular Geometry
« Reply #1 on: December 02, 2006, 03:36:06 AM »
Yup.
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Offline saN

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Re: Molecular Geometry
« Reply #2 on: December 02, 2006, 04:32:57 AM »
For C2HClBrF, I ended with 9 isomers. Correct?
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Offline Yggdrasil

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Re: Molecular Geometry
« Reply #3 on: December 02, 2006, 05:39:23 AM »
Can you draw out all 9 isomers?  I count only 3.
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Offline saN

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Re: Molecular Geometry
« Reply #4 on: December 02, 2006, 07:04:05 PM »
Would 1 and 6, 2 and 5, 3 and 4, 5 and 7, 4 and 8, 6 and 9 be isomers of each other? This would leave only 1, 2, and 3 be the only isomers?
« Last Edit: December 06, 2006, 08:11:14 PM by saN »
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Offline Borek

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Re: Molecular Geometry
« Reply #5 on: December 02, 2006, 07:09:37 PM »
I suppose Ygg missed the fact that is alkene, not alkane. But you are wrong too. For example: 6 & 9 are identical.
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Offline saN

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Re: Molecular Geometry
« Reply #6 on: December 02, 2006, 07:53:11 PM »
So, does that mean there are 6 isomers, the first 6?

But isn't 2 and 5 the same? 3 and 4 the same? 1 and 6 the same? This leaves the first 3 (1,2,3) to be the only isomers?
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Offline Borek

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Re: Molecular Geometry
« Reply #7 on: December 02, 2006, 08:26:46 PM »
Not checking others: 3 & 4 are different. Double bond is flat and doesn't rotate.
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Offline saN

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Re: Molecular Geometry
« Reply #8 on: December 02, 2006, 08:36:31 PM »
I can't believe that I spaced out that double bonds do not rotate. This will definately help me! Thanks a lot!
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Offline saN

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Re: Molecular Geometry
« Reply #9 on: December 03, 2006, 02:37:59 AM »
Well, I went through it again and ended up with 6 isomers, the first 6.
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