[Sodium-Potassium Pump]

Okay, here's the problem:

A microwave oven utilizes microwave photons that are absorbed by water molecules thereby heating material containing water.  Suppose a Hostess Twinkie(TM) that contains 25 g of water is zapped for 30 seconds at a power of 200 watts (watt = joule/sec) with microwaves of wavelength 0.50 cm.  How many microwave photons are absorbed by each water molecule in the Twinkie(TM)?  The water in the Twinkie(TM) has a heat capacity of 4.184 J/g x C.  By how much is the temperature of the water in hte Twinkie(TM) raised?
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Ok, I think I've worked some out and would appreciate some help as to whether or not I'm doing the right thing. Solving the problem with work as well would be appreciated but isn't necessary.

So here's what I've done:

E = hv and v = c/wavelength

v = 2.99x10⁸ m/sec / 0.005 m
v = 6.00 x 10¹⁰

E = (6.6256x10^-34 Jxsec) (6x10¹⁰)
E = 3.97x10^-23 J/photon
E = 3.97x10^-23 J/photon x (6.022x10²³)
E = 23.91 J/mol

then I went ahead and figured

25 g H₂O / 15 g/mol H₂O
= 1.39 mol H₂O

 1.39 mol H₂O x (23.91 J/mol) = 33.23 J/mol of H₂O

so 33.23 J/mol H₂O x (1 mol H₂O  / 6.022x10²³) = 5.52x10^-23 J/molecule of H₂O

Is that correct?  How do I figure the second part of the question?

I know that C = Q / delta T so the change in temperature = q / C

I'm not sure what I'm supposed to use for q

Thanks in advance for any *delete me*

[sdekivit]

how many photons are absorbed isn't answered yet. Hint: you know the transferred energy in 30 seconds is 30 * 200 = 6000 J.

-->you know the energy of 1 photon that can be calculated with E = hc/lambda.

How many photons are then absorbed by the twinkie ? And thus how many per H2O-molecule ?

Then 6000 J is absorbed by 25 g water, thus using Q = c * m * delta T will result in the delta T of the water in the twinkie (when 6000 J is absorbed in the 30 seconds in the microwave)