A pretty simple experiment also would be to just take a UV/vis spectrum of the sample. If the Iron only had 4 ligands it would be either square-planar or tetrahedral geometry, there would be relatively low splitting energy, and the complex would be high-spin. If it was high spin there would be 5 equally occupied d-orbitals and you wouldn't see any d-d transitions in the UV/vis spectrum, only charge-transfer bands.
Iron(III) coordinated to 6 SCN-, however, would be in octahedral geometry with a fairly strong ligand field and would be low spin, meaning you would likely see 4 clear d-d transitions and 2 charge transfer bands.