Balance the equation and consider the coefficients.
KClO3 + HCl --> KCl + H20 + Cl2 + ClO2
If x = coefficient of KlCO3 and y = coefficient of ClO2, find the other coefficients in terms of x and y (I had a x+y in my notes but it's confusing at the moment so I am assuming it is and.)
I've balanced the equation many times and have gotten the answers but now I must find the coefficients in terms of x and y. I think I have balanced the equation enough times to accomplish this.
2,4,2,2,1,2
3,10,3,5,4,2
4,16,4,8,7,2
5,14,5,7,5,4
6,12,6,6,3,6
9,46,9,23,22,2
The coefficients are inorder with the equation. For example, the first one i listed (2,4,2,2,1,2):
The first 2 stands for 2 moles of KClO3 while the 4 stands for 4 moles of HCl.
I have attempted to find the other coefficients in terms of X and Y but have only found minimal success. So somehow Y, which has 3 coefficients with 2,must equal to different numbers using the same equation. My explanation might not be very good, but for example x = 2 and HCl =4. Then to express HCl in terms of x, HCl=2x. What I'm wondering is how can y = 2 be 1, 4, and 7 at the same time using the same equation.
KCl is equal to x is all i got.
I might be comprehending this wrong, and if so, please tell me.