[h20h]

Q:  If 20mL of a 0.3M solution of NaOH is required to neutralize 30.0 mL of a sulfuric acid solution, what is the molarity of the acid solution?  H2SO4 + 2NaOH = Na2SO4 + 2H20

A)  This is what I did:  I took the 20 ml and converted to Liters= .02 Liters....then took that and converted to moles by multiplying .02 and .3/1 liter which came out to be .006 moles of NaOH.  Since the stoich is 1:2  you have to take the .006 moles of NaOH and divide by 2 giving you .003 moles of H2SO4..

I then took the 30mL converted to liters giving me .03 liters, and then took the .003 moles of H2SO4 and divided it by .03 liters and got a .1M acidic solution??

Help here, right wrong? 

Thanks

[kristo]

That looks good to me. Good explanation while you were working the problem.

[h20h]

Thanks for your *delete me*