Hi Borek, ok I did what you asked..., can you please tell me if the following answer is correct?
the cell potential of the solution is measured in reference to the SHE, which has a value of 0 by definition.
using E(cell) = -0.0592 log[H+]
and thus, pH =E(cell) / -0.0592 = -0.324 / -0.0592 = 5.47
Is this correct?
Thanks a lot.