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Topic: Titration Problems  (Read 4209 times)

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Offline colormelovibond

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Titration Problems
« on: April 25, 2007, 12:36:10 PM »
This is such a simple problem, I feel silly asking it.  But...

It a simple acid-base titration.  I am titrating sodium methylate with hcl to determine the concentration.

The HCL is 37 % = 12.11 mol HCl/liter of solution.

Sodium Methylate MW = 54.03

If I add 13 mL of HCL to 150mL methylate, what is the concentration of the methylate in terms of moles and percentage?  What calculation do I use? 

Thanks so much!

 

Offline Borek

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Re: Titration Problems
« Reply #1 on: April 25, 2007, 01:22:35 PM »
Start with reaction equation.
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Offline colormelovibond

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Re: Titration Problems
« Reply #2 on: April 25, 2007, 03:20:47 PM »
The reaction equation is
  NaOCH3 + HCl --> NaCl + HOCH3

It took 13 mL of HCl to neutralize the sodium methylate.


Offline Borek

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Re: Titration Problems
« Reply #3 on: April 25, 2007, 03:56:38 PM »
I suppose you mean sodium methanolate (metoxide), mot methylate?

Dont think in terms of mL, think in terms of moles. How many moles of HCl? What is molar ratio acid and methanolate react? How many moles of methanolate?

Are you sure you were using concentrated HCl?

You will need density of methanolate solution for the percentage.
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