Dear Katrina007,
(Sorry, dear Yggdrasil, but I can understood, if Katrina007 has made their decision out, more of her stomach, then of real knowledge of the required “Phase-Diagram” of Water.)
To answer the question, you must first know the so called “Phase-Diagram” of Water, and realise at the same time, that you have to keep the pressure all times constant at 1.0 atm.
That means that you have to draw a line into the graph at this const. pressure and make the required proof for your answers.
Now you can easily see, that at 105°C only H2 O(g) is existing on your Line, and that means, if you are able to bring H2 O(l) to 105°C, it will dramatically (mini explosion like) change to the gaseous state, at least as long as enough energy is usable.
On the other hand, you will see too, that it is impossible to generate ice under this condition (25°C), because the first time ice can exist on your Line is just at 0°C (or below), where your line is crossed from the phase-line of water-ice, which tells you that at that temperature both aggregate states exist at the same time.
Now it’s only left to you to correctly classify/determine the resulting Spontaneity of the postulated “reactions” of your question.
I hope it’s not too difficult anymore.
Good Luck!
ARGOS++