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Topic: Going from mL to mg/L potassium phosphate  (Read 5006 times)

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Offline pcubis

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Going from mL to mg/L potassium phosphate
« on: April 22, 2007, 12:19:21 PM »
I have 3.6 mL of potassium phosphate in a 180 L solution.  I want to know how many mg/L of K is in that solution.  Any help would be greatly appreciated.  Thank you in advance. :)

Offline Yggdrasil

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Re: Going from mL to mg/L potassium phosphate
« Reply #1 on: April 22, 2007, 02:06:47 PM »
Potassium phosphate is a solid, so it doesn't make sense to talk about mL of potassium phosphate.  Do you mean that you have 3.6mL of a potassium phosphate solution diluted in 180L?  In this case you would need to know the concentration of your potassium phosphate solution and use MinitialVinitial = MfinalVfinal to find the molarity in the dilution.

Offline pcubis

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Re: Going from mL to mg/L potassium phosphate
« Reply #2 on: May 09, 2007, 02:39:42 PM »
Potassium phosphate is a solid, so it doesn't make sense to talk about mL of potassium phosphate.  Do you mean that you have 3.6mL of a potassium phosphate solution diluted in 180L?  In this case you would need to know the concentration of your potassium phosphate solution and use MinitialVinitial = MfinalVfinal to find the molarity in the dilution.

I am sorry.  Yes, I do mean that I have 3.6 mL potassium phosphate solution diluted in 180L.  The equation I am familiar with but I am still confused.  If I am only given that much info.  I was wondering if there was a way of working backwards to attain the concentration? Thank you for your response. 

Offline Yggdrasil

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Re: Going from mL to mg/L potassium phosphate
« Reply #3 on: May 09, 2007, 07:59:07 PM »
You currently do not have enough information to determine the concentration of potassium in your dilution.

Offline pcubis

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Re: Going from mL to mg/L potassium phosphate
« Reply #4 on: May 15, 2007, 10:15:19 PM »
You currently do not have enough information to determine the concentration of potassium in your dilution.

I finally tracked down the person that made the solution and got them to tell me the concentration.  I appreciate your responses in attempt to help me.  :) 

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