What is the maximum number of grams of PH3 that can be formed when 6.2 grams of phosphorus reacts with 4.0 grams of hydrogen to form PH3?
P4 + 6H2 ----> 4PH3
6.2 g * (1 mol / 31 g) = 0.2 mol of P (LIMITING REACTANT)
4.0 g * (1 mol / 1 g) = 4 mol of H2
So...
6.2 g * (1 mol / 124 g) * (4 mol / 1 mol) * (34 g / 1 mol) = 6.8 g of PH3
Is that correct?