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Topic: Iodination of salicaldehyde mechanism  (Read 6641 times)

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Offline Rakkoonn

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Iodination of salicaldehyde mechanism
« on: May 30, 2007, 02:44:47 PM »
What will this reaction mechanism look like? McMurry's book tells me that iodine isn't very reactive with benzene. We've got OH group, which activates meta and para positions so I guess that makes it easier for the reaction to occur. But why do we need to add NaOH & NaHCO3 before introducing I2 in KI?

« Last Edit: May 31, 2007, 03:08:42 AM by Rakkoonn »

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