Hello!
I am not sure how to reduce the product by using LiAlH4 in the second sequence. This is what I think we would get after steps 1, 2, and 3 of the first sequence. I have shown my work as a attachment in the following message...
these are the choices for the final product:
A) PhCOOH
B) PhCH2COOH
C) PhCHO
D) PhCH2OH
thank you!