Hmmm...according to the patent, 3a is a trityl chloride made from 2a. So, I looked back at 2a. They say that they make 2a by reacting suberyl chloride (
http://www.orgsyn.org/orgsyn/chemname.asp?nameID=38799) with alcohol 1a to give the "dicarboxylic acid ester" 2a. Clearly this is a mistake because suberyl chloride is labeled 1a and it isn't an alcohol! They mean alcohol 2b, which is 3-hydroxy-4,4-dimethoxytriphenylcarbinol. Now, whoever wrote this patent doesn't know how to name structures but I'm almost sure that they meant to write bis(4-methoxyphenyl)(phenyl)methanol. Think of it as trityl alcohol where two of the benzene rings have a methoxy group in the 4 position.
NOW, if you react bis(4-methoxyphenyl)(phenyl)methanol 2b with suberyl chloride to make "dicarboxylic acid ester" 2a, that gives you a diester with this structure: (dimethoxytrityl ester)(CH
2)
5(dimethoxytrityl ester).
I suppose it is conceivable that they made dimethyoxytrityl chloride (
http://www.chemexper.com/chemicals/supplier/cas/40615-36-9.html) by reacting "dicarboxylic acid ester" 2a with acetyl chloride but it seems stupid. I would just react bis(4-methoxyphenyl)(phenyl)methanol 2b with thionyl chloride. There is no need to esterify 2b.