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Offline imevil555

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Topic Closed
« on: August 24, 2007, 08:22:05 PM »
Topic Closed
« Last Edit: December 15, 2007, 03:44:26 PM by imevil555 »

Offline enahs

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Re: Barium Ion Concentration?
« Reply #1 on: August 24, 2007, 08:38:19 PM »
0.02L * 0.300 M K2CO2 = 6x10-3 mols K2CO3 = 2 * (6x10-3 mols K(aq)) + 6x10-3 mols CO3 (aq)
0.06L * 0.600 M Ba(NO3)2 = 0.036 mols Ba(NO3)2 = 0.036 mols Ba (aq) + 2* ( 0.036 mols (NO3)2 )



After the reaction, how many mols of Ba are left? In what total volume is it in?


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