[pat007]

Wht volume of hydrogen chloride gas is produced by the reaction of 40cubic cms of chlorine with hydrogen (excess)? (All gas volumes are measured at room temperature and pressue).

Only the vol of CL2 was given (40cm3).
I did the following:
cl2 + h2= 2hcl
71 + 2 = 73
ratio: 1g cl2 produces 73/71 of hcl.
1g cl2= 1.03g hcl

71g=1mol=24dm3
1dm3 = 2.96g
.040dm3 = .118g
.118g of cl2 x 1.03g = 0.122g hcl
73g hcl= 24dm3 then 0.122g = 24/73 x .122g= .040dm3.

Yes .040dm3 is clearly incorrect. What am I missing? Is there a simpler way to calculate this?

[Borek]

No such things as hcl, cl2 or h2.

No need to go through masses - moles can be converted directly to volumes.

73g hcl= 24dm3

Try harder

[AWK]

Cl2 + H2= 2HCl
Look at the stoichiometry of this reaction. Moles and volumes are proportional at the same temperatute and pressure

[pat007]

Thanks for the response.