[mb85]

Hello.
i need to propose a structure based on C3H5Br that has no protons on one carbon.
i have drawn all 5 isomers of C3H5Br.

But im curious if my proposed structure is correct?

CH3CH2-C(+) Br(-) and have them interact as an ion?

or is there another way to go about the structure?

[Borek]

No ions involved isomer can be drawn, although it is unstable.

[mb85]

so then just...

CH3CH-C(lone pair attached)-Br

?

[Borek]

No primary carbons in the correct structure.

[mb85]

so it resembles the ring isomer then?
just not seeing how 5 H's can be on that structure without breaking the 4 bonds to carbon rule.

[Borek]

so it resembles the ring isomer then?

Right.

just not seeing how 5 H's can be on that structure without breaking the 4 bonds to carbon rule.

To what atoms can be carbon connected?

[Yggdrasil]

I don't think that the solution is a cyclic compound.  Also (unless I've missed something), the correct isomer should be one of the five isomers.  Could you somehow show or list the isomers that you've drawn out?

[mb85]

wow.... yggdrasil.. u are exactly right. it was one of the five isomers i drew.
i cant believe i overlooked it.

here it is.

H2C=C (and then attached to that C are both Br and CH3).

thanks.

[Borek]

Somehow I have read the original post as C₃H₃Br... Most likely because the real answer is so obvious I was sure it must be something harder to find