[is3zzz]

Question: A metal has a density of 11.67 g/cm3.  214.71 g of this metal are molded into the shape of a perfect sphere.  What is the diameter of this sphere in cm?
Error tolerance:  ±0.1%
Answ: 7.026 cm ?

I was wondering if anyone else came up with the same answer as I did with this question.
My attempt:
volume= 214.71g divided by 11.67 g/cm³ = 18.40 cm³
r=((v)(3/4Pi))^1/3 = 7.026

[Yggdrasil]

A few problems:

1) you solved for the radius, not the diameter
2) although your formula for the radius is correct, the number you get at the end is not right.  Are you sure that you are dividing by pi and not multiplying by it (for example if you type: 3/4π into a calculator, it will interpret this as 3 /4 * π  = 3 * π / 4.  Typing 3/(4π) gives you the result you need.)

(NB: if you are unsure if you rearranged a complicated expression correctly, you can always try plugging the answer back into the original equation.  So if you try to calculate the volume with a radius of 7.026, you get:

V = (4/3)π*(7.026cm)^3 = 1453cm³

which is obviously not the right volume)

[is3zzz]

my new answer is now 3.275 cm? How does that sound now? Also, my error tolerance is +/- 0.1%, are my significant figures okay?

since r= (18.40)(3/4p^1/3i)
r=1.638
d=3.275 cm

[Haunted Chmist]

After what I calculated the given values, I got the answer 3.274 cm. Anybody with same answer?

STEP 1: Finding Volume; Volume =18.398 cc.
STEP 2: Finding Radius; Radius = 1.6374 cm by the formula - Volume of Sphere = (4/3) * Pi* Cubic Radius, and then finding the cuberoot of the so found cubic radius.
STEP 3: Finding the diameter which is 2 times radius, which I got 3.2749 cm.

Anybody same here?